They've 2m
Web23 Jan 2024 · Leave blank 8 *P48326A0828* 3. 120° 6N 7N Q O P Figure 1 Two forces P and Q act on a particle at a point O.Force P has magnitude 6 N and force Q has magnitude 7 … Web14 May 2024 · 3 Answers. Worthy of mention is that 432MHz is a harmonic of 144MHz, meaning that the antenna can be much simpler; if it's (electrically) an odd number of half-waves on 2m, it's also an odd number of half-waves on 432MHz. Oh this is good! Didn't realize that relationship had such a practical effect.
They've 2m
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Web5 Jun 2024 · P41828A 3 4. A lorry is moving along a straight horizontal road with constant acceleration. The lorry passes a point A with speed u m s–1, (u < 34), and 10 seconds later passes a point B with speed 34 m s–1.Given that AB = 240 m, find (a) the value of u, (3) (b) the time taken for the lorry to move from A to the mid-point of AB.(6) 5. WebLeave blank 8 *n26115A0824* 4. Figure 2 Two particles A and B, of mass m and 2m respectively, are attached to the ends of a light inextensible string. The particle A lies on a rough plane inclined at an angle α to the horizontal, where tan α = . The string passes over a small light smooth pulley P fixed at the top of the plane.
Web23 Jun 2024 · Current evidence suggests being 1m apart carries between two and 10 times the risk of being 2m apart, scientists advising the government have said. Under new guidance, the government wants people... Web14 Jun 2024 · The impulse is at 5mu and as I=mv-mu you can find the speed of P. Take the Impulse in the positive direction (i.e. to the left) therefore the initial speed of 2u is negative in the impulse equation and the final velocity is also negative (I labelled X). Then you get 5mu = 2m (-X- - 2u) 5mu = 2m ( 2u - X) 5mu = 4mu - 2mX mu=-2mX X= -0.5u
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